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📋 DSSSB Optometrist 2026 · Post Code 09/26
📄 2019 Paper
DSSSB Optometrist
Previous Year Paper 2019
Part 2 — Q21 to Q38
18 actual questions from DSSSB Optometrist 2019 exam covering Optics, Retinoscopy, CXL, Prisms & Clinical Refraction — click any option to reveal the answer instantly.
📅 Exam Year: 2019
❓ Questions: Q21–Q38
📌 Vacancies 2026: 15 Posts
⏰ Last Date: 28 Mar 2026
This blog contains questions Q21 to Q38 from the DSSSB Optometrist 2019 Previous Year Paper with correct answers and detailed explanations. Topics covered: Retinoscopy, Corneal Collagen Cross-linking, YAG iridotomy, Geometrical & Physical Optics, Prisms, Lens Combinations, Clinical Refraction, and Visual Acuity assessment.
How to use: Read each question → click your chosen option → the correct answer and full explanation appear immediately. Your live accuracy score is tracked in the floating card on the right.
📑 Questions in This Part (Q21–Q38)
Q21 — Retinoscopy with Plane Mirror
Q22 — Peribulbar Block Location
Q23 — Corneal Collagen Cross-linking
Q24 — YAG Iridotomy Drug
Q25 — Interference of Light
Q26 — Polarised Light
Q27 — Astigmatic Lens Refraction
Q28 — Thin Lens Combination
Q29 — Reduced Schematic Eye Focal Points
Q30 — Aberrations — False Statement
Q31 — Prescription Transposition
Q32 — Spherical Equivalent for CL
Q33 — Image Formed by Prism
Q34 — Critical Angle & TIR
Q35 — Prism Dioptre Displacement
Q36 — Spherocylindrical Lens Notation
Q37 — Visual Acuity in Toddler
Q38 — Visual Acuity — True Statement
Q-21
While performing retinoscopy with a plane mirror, which statement is NOT true? (DSSSB Optometrist Previous Year Question Paper)
DSSSB Optometrist 2019 — Clinical Refraction👆 Click an option to check your answer
✓ Correct Answer: A
A ‘with’ movement does NOT exclusively indicate hypermetropia. It is also seen in emmetropia and in low myopia where the patient’s far point is behind the examiner. Only when the far point is at infinity or beyond does it confirm emmetropia/hypermetropia. Option B is true: ‘with’ is neutralised with a plus lens. Option C is true: ‘against’ is neutralised with a minus lens. Option D is true: ‘against’ means the far point is between examiner and patient (myopia higher than working distance).
Q-22
The peribulbar block is given in: (DSSSB Optometrist Previous Year Question Paper)
DSSSB Optometrist 2019 — Ocular Anaesthesia👆 Click an option to check your answer
✓ Correct Answer: D. Outside the muscle cone
Peribulbar block = injection into the extraconal space (outside the muscle cone). The anesthetic diffuses around the globe to provide akinesia and anesthesia. Contrast with Retrobulbar block which is intraconal (inside the muscle cone). Peribulbar is safer because it avoids the optic nerve sheath and reduces risk of globe perforation.
Q-23
Corneal collagen cross-linking is done in keratoconus by: (DSSSB Optometrist Previous Year Question Paper)
DSSSB Optometrist 2019 — Ocular Diseases👆 Click an option to check your answer
✓ Correct Answer: D. Riboflavin + UV-A
Corneal Collagen Cross-linking (CXL) for keratoconus uses Riboflavin (Vitamin B2) as a photosensitizer activated by UV-A light (370 nm). This creates new covalent bonds between adjacent collagen fibers → stiffens and strengthens the corneal stroma → halts keratoconus progression. Key mnemonic: R + A — Riboflavin + UV-A. UV-C is germicidal and not used clinically.
⏰ Deadline: 28 March 2026
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Q-24
Prophylactic YAG peripheral iridotomy is being done. Which drug will you instil before the procedure? (DSSSB Optometrist Previous Year Question Paper)
DSSSB Optometrist 2019 — Ocular Pharmacology👆 Click an option to check your answer
✓ Correct Answer: C. Pilocarpine
Pilocarpine (miotic/parasympathomimetic) is instilled before Nd:YAG peripheral iridotomy. It causes miosis → constricts the pupil → stretches and thins the peripheral iris → makes it easier to penetrate with the laser. Tropicamide/Homatropine (mydriatics) and Phenylephrine (alpha agonist) would DILATE the pupil — the opposite of what is needed.
Q-25
Which statement is true with regard to the interference of light? (DSSSB Optometry MCQs with Answers)
DSSSB Optometrist 2019 — Physical Optics👆 Click an option to check your answer
✓ Correct Answer: A
Anti-reflective (AR) coatings work on the principle of destructive interference — a microscopic metal oxide layer is applied so that reflected waves from its inner and outer surfaces are exactly half a wavelength out of phase → they cancel each other → more light is transmitted → reduced glare. Corneal transparency is due to destructive interference (not constructive) of scattered light from regularly arranged collagen fibrils.
Q-26
Which of the following is NOT correct about polarised light? (DSSSB Optometry MCQs with Answers)
DSSSB Optometrist 2019 — Physical Optics👆 Click an option to check your answer
✓ Correct Answer: C. Sunlight is polarised
Sunlight is UNPOLARISED — its waves vibrate in multiple random planes perpendicular to the direction of travel. Light becomes polarised only after reflecting off flat non-metallic surfaces (water, roads, snow). Ophthalmic instruments like binocular indirect ophthalmoscopes, Titmus stereo test, and Worth’s 4-dot test DO use polarised light (Option B is correct). Polarising filters DO reduce glare (Option D is correct).
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Q-27
The refraction of light through astigmatic lenses is in the form of a: (DSSSB Optometry MCQs with Answers)
DSSSB Optometrist 2019 — Geometrical Optics👆 Click an option to check your answer
✓ Correct Answer: C. Sturm’s Conoid
An astigmatic lens has unequal power in two principal meridians → creates two perpendicular focal lines (not a single focal point). The 3D bundle of light rays between these two focal lines is the Conoid of Sturm. At the midpoint between the two focal lines is the circle of least confusion — where the spherical equivalent prescription falls. This is a very high-yield optics concept in DSSSB exams.
Q-28
Two thin lenses of +2D and -1D placed in contact: what is the focal length of the combination? (DSSSB Optometrist Solved Papers PDF)
DSSSB Optometrist 2019 — Geometrical Optics👆 Click an option to check your answer
✓ Correct Answer: D. 1 m
For thin lenses in contact, combined power = P₁ + P₂ = (+2D) + (−1D) = +1D. Focal length = 1/P = 1/1 = 1 metre. Key formula: Pcombined = P₁ + P₂ (only valid when lenses are in contact, not separated). This is a guaranteed calculation question in every DSSSB optics section.
Q-29
In the reduced schematic eye, anterior and posterior focal points measured from the anterior corneal surface are: (DSSSB Optometrist Solved Papers PDF)
DSSSB Optometrist 2019 — Geometrical Optics👆 Click an option to check your answer
✓ Correct Answer: A. 17 mm and 22.6 mm
The Reduced Schematic Eye represents all refracting surfaces as one single surface (at the anterior cornea). Standard values: Primary (anterior) focal point = 17 mm in front of the surface. Secondary (posterior) focal point = 22.6 mm behind the surface (this is where the retina lies in an emmetropic eye). Option B reverses these — the classic exam trap.
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Q-30
Regarding aberrations, which statement is FALSE? (DSSSB Optometrist Solved Papers PDF)
DSSSB Optometrist 2019 — Geometrical Optics👆 Click an option to check your answer
✓ Correct Answer: C. Coma is oblique astigmatism
Coma and Oblique Astigmatism are both monochromatic higher-order aberrations, but they are distinct phenomena. Coma produces a comet-like asymmetric blur (varying magnification across the pupil). Oblique astigmatism creates two perpendicular focal lines for off-axis points. Option A is TRUE: dilated pupil uses peripheral zones with more spherical aberration. Option B is TRUE: Duochrome (red-green) test exploits chromatic aberration of the eye.
Q-31
A patient with prescription -4DS/+1DC x 90° is unhappy. Change the prescription to minus-cylinder form. What will be the new prescription? (DSSSB Optometrist 2026 preparation)
DSSSB Optometrist 2019 — Clinical Refraction / Dispensing👆 Click an option to check your answer
✓ Correct Answer: C. -3DS / -1DC x 180°
Prescription Transposition steps: ① New sphere = old sphere + old cylinder = -4.00 + (+1.00) = -3.00 DS ② New cylinder = invert the sign of old cylinder = -1.00 DC ③ New axis = old axis ± 90° = 90° + 90° = 180°. Result: -3.00DS / -1.00DC × 180°. This is the most commonly tested calculation in the clinical refraction section of DSSSB.
Q-32
You want to prescribe spherical contact lenses to a patient with prescription -3DS/-1DC x 45°. What is the spherical equivalent? (DSSSB Optometrist 2026 preparation)
DSSSB Optometrist 2019 — Contact Lens / Refraction👆 Click an option to check your answer
✓ Correct Answer: D. -3.50 DS
Spherical Equivalent (SE) = Sphere + ½ Cylinder = -3.00 + (½ × -1.00) = -3.00 + (-0.50) = -3.50 DS. The SE places the circle of least confusion on the retina, providing the best average spherical focus for a patient with astigmatism when prescribing spherical contact lenses. Always remember: SE = S + C/2.
Q-33
The image formed by a prism is: (DSSSB Optometrist 2026 preparation)
DSSSB Optometrist 2019 — Geometrical Optics / Prisms👆 Click an option to check your answer
✓ Correct Answer: D. Shifted towards the apex
A prism deviates light rays toward the base. Because the visual system projects these incoming rays backward in a straight line, the image appears displaced toward the apex. The prism image is: Virtual (not real), Erect (not inverted), and Displaced toward the apex. In clinical practice: Base-in prism shifts image inward → used for esotropia. Base-out shifts image outward → used for exotropia.
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Q-34
Which is NOT true regarding critical angle and total internal reflection? (DSSSB Optometrist 2026 preparation)
DSSSB Optometrist 2019 — Physical Optics👆 Click an option to check your answer
✓ Correct Answer: D
A goniolens does NOT decrease the critical angle. Instead, it index-matches the cornea (using a coupling fluid), eliminating the cornea-air interface entirely. Without the air interface, light from the anterior chamber angle can exit without undergoing total internal reflection. Options A, B, C are all TRUE. This is a very important concept for Gonioscopy questions in DSSSB exams.
Q-35
A prism of 1 prism dioptre will displace the image of an object placed 100 cm away by: (DSSSB optometry MCQs with answers PDF)
DSSSB Optometrist 2019 — Geometrical Optics / Prisms👆 Click an option to check your answer
✓ Correct Answer: B. 1 cm
1 Prism Dioptre (1Δ) = displaces a light beam by 1 cm on a screen placed 1 metre (100 cm) away. This is the standard definition by Prentice. Formula: Deviation (cm) = Power (Δ) × Distance (m). So 1Δ × 1m = 1 cm. This basic prism dioptre definition is asked in almost every government optometry examination.
Q-36
Regarding the notation of spherocylindrical lenses, which is NOT true? (DSSSB optometry MCQs with answers PDF)
DSSSB Optometrist 2019 — Optics / Dispensing👆 Click an option to check your answer
✓ Correct Answer: A. 0° is same as 180°
While geometrically 0° and 180° are the same horizontal plane, in TABO clinical notation the horizontal axis is always recorded as 180°, never as 0°. Using 0° would cause manufacturing errors. This is the standardised convention adopted globally. Options B, C, D are all TRUE: same scale for both eyes, TABO adopted in 1947, and a spherocylindrical lens is indeed equivalent to two plano-cylinders at perpendicular axes.
Q-37
You have a toddler who cannot speak. To assess visual acuity, which instrument will you NOT use? (DSSSB optometry MCQs with answers PDF)
DSSSB Optometrist 2019 — Visual Acuity / Paediatric Optometry👆 Click an option to check your answer
✓ Correct Answer: A. Bailey-Lovie chart
The Bailey-Lovie chart requires letter recognition and verbal responses — completely unusable for a pre-verbal toddler. Paediatric VA tests: Cardiff cards (preferential looking, acuity cards), Catford drum (optokinetic nystagmus), Sheridan-Gardiner (picture/shape matching, can point). Remember: Bailey-Lovie, Snellen, ETDRS all need verbal cooperation — not for toddlers.
Q-38
Regarding visual acuity, which of the following statements is TRUE? (DSSSB Optometrist 2019 solved paper)
DSSSB Optometrist 2019 — Visual Acuity👆 Click an option to check your answer
✓ Correct Answer: D
The Sheridan-Gardiner test is a validated method for testing VA through shape matching — TRUE. Option A is FALSE: Normal vision = 6/6, not 5/6. Option B is FALSE: Pupil size greatly affects depth of focus and resolution (large pupil → more aberrations → worse acuity). Option C is FALSE: Normal VA resolution is 1 minute of arc (not 10). The minimum angle of resolution (MAR) for normal 6/6 vision is exactly 1 arcminute.
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❓ Frequently Asked Questions
What topics does DSSSB 2019 Part 2 (Q21–Q38) cover? ▼
Part 2 covers Retinoscopy (with/against movements), Peribulbar block, Corneal Collagen Cross-linking (CXL), YAG iridotomy, Physical Optics (interference, polarised light), Geometrical Optics (Sturm’s conoid, prisms, aberrations), Clinical Refraction (prescription transposition, spherical equivalent), and Paediatric Visual Acuity testing.
What is the formula for prescription transposition to minus cylinder form? ▼
Three steps: ① New Sphere = Old Sphere + Old Cylinder (algebraically add them). ② New Cylinder = invert the sign of the old cylinder. ③ New Axis = old axis ± 90° (always between 1° and 180°). Example: -4DS/+1DC×90° becomes: New S = -4+1 = -3DS, New C = -1DC, New Axis = 90+90 = 180°. Final: -3DS/-1DC×180°.
How is spherical equivalent calculated for contact lens prescription? ▼
Spherical Equivalent (SE) = Sphere + ½ × Cylinder. For -3DS / -1DC × 45°: SE = -3.00 + (-1.00/2) = -3.00 + (-0.50) = -3.50 DS. SE is used when prescribing spherical contact lenses for patients with astigmatism as it places the circle of least confusion on the retina.
Is DSSSB 2019 paper relevant for DSSSB 2026 preparation? ▼
Absolutely. Topics like retinoscopy movements, Sturm’s conoid, prism dioptre, spherical equivalent, CXL for keratoconus, prescription transposition, and visual acuity testing methods have appeared repeatedly across DSSSB exam cycles. Mastering 2019 PYQs directly improves your DSSSB 2026 performance.
